A particle is projected with velocity v0 along x-axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e. ma = - αx2. The distance at which the particle stops:

Option 1 -

( 2 v 0 3 α ) 1 3

Option 2 -

( 3 v 0 2 2 α ) 1 2

Option 3 -

( 2 v 0 2 3 α ) 1 2

Option 4 -

( 3 v 0 2 2 α ) 1 3

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:

    F = α x 2 m v d v d x = α x 2

    v 0 0 v d v = α m 0 x x 2 d x 0 2 2 v 0 2 2 = α 3 m x 3

    v 0 2 2 = α 3 m x 3 x = ( 3 v 0 2 m 2 α ) 1 / 3

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