A particle moves in a circular orbit of radius r under a central attractive force F =
k is constant. The time period of its motion is proportional to
A particle moves in a circular orbit of radius r under a central attractive force F = k is constant. The time period of its motion is proportional to
Option 1 -
r1/2
Option 2 -
r
Option 3 -
r2/3
Option 4 -
r3/2
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1 Answer
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Correct Option - 2
Detailed Solution:
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. (i)
. (ii)
= 107 m
= 10,000 km
R + h = 10,000
h = 10,000 – 6400 = 3600 km
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