A particle of charge <math> <mi>q</mi> </math> and mass <math> <mi>m</mi> </math> is subjected to an electric field <math> <mi>E</mi> <mo>=</mo> <msub> <mrow> <mrow> <mi>E</mi> </mrow> </mrow> <mrow> <mrow> <mn>0</mn> </mrow> </mrow> </msub> <mfenced separators="|"> <mrow> <mrow> <mn>1</mn> <mo>-</mo> <mi>a</mi> <msup> <mrow> <mrow> <mi>x</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> </mrow> </mrow> </mfenced> </math> in the <math> <mi mathvariant="normal">x</mi> </math> -direction, where <math> <mi>a</mi> </math> and <math> <msub> <mrow> <mrow> <mi mathvariant="normal">E</mi> </mrow> </mrow> <mrow> <mrow> <mn>0</mn> </mrow> </mrow> </msub> </math> are constants. Initially the particle was at rest at <math> <mi mathvariant="normal">x</mi> <mo>=</mo> <mn>0</mn> </math> . Other then the initial position the kinetic energy of the particle becomes zero when the distance of the particle from the origin is:

Sol. E= (I) (t) (A)cos2? θ⇒ (3.3)2π31.43×10-4×12⇒0.99×10-4

A particle of charge <math> <mi>q</mi> </math> and mass <math> <mi>m</mi> </math> is subjected to an electric field <math> <mi>E</mi> <mo>=</mo> <msub> <mrow> <mrow> <mi>E</mi> </mrow> </mrow> <mrow> <mrow> <mn>0</mn> </mrow> </mrow> </msub> <mfenced separators="|"> <mrow> <mrow> <mn>1</mn> <mo>-</mo> <mi>a</mi> <msup> <mrow> <mrow> <mi>x</mi> </mrow> </mrow> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> </msup> </mrow> </mrow> </mfenced> </math> in the <math> <mi mathvariant="normal">x</mi> </math> -direction, where <math> <mi>a</mi> </math> and <math> <msub> <mrow> <mrow> <mi mathvariant="normal">E</mi> </mrow> </mrow> <mrow> <mrow> <mn>0</mn> </mrow> </mrow> </msub> </math> are constants. Initially the particle was at rest at <math> <mi mathvariant="normal">x</mi> <mo>=</mo> <mn>0</mn> </math> .&nbsp;Other then the initial position the kinetic energy of the particle becomes zero when the distance of the particle from the origin is:

<math> <mroot> <mrow> <mrow> <mfrac> <mrow> <mrow> <mn>2</mn> </mrow> </mrow> <mrow> <mrow> <mi>a</mi> </mrow> </mrow> </mfrac> </mrow> </mrow> <mrow></mrow> </mroot> </math> (Elecrtrostatics)

Ask & Answer Question

Physics Class 12th Physics Electric Charge and Field physics ncert exemplar solution class 12th chapter one

A particle of charge $q$ and mass $m$ is subjected to an electric field $E = E_{0} (1 - a x^{2})$ in the $x$ -direction, where $a$ and $E_{0}$ are constants. Initially the particle was at rest at $x = 0$ . Other then the initial position the kinetic energy of the particle becomes zero when the distance of the particle from the origin is:

Option 1 -

$\sqrt[]{\frac{3}{a}}$

Option 2 -

$\sqrt[]{\frac{1}{a}}$

Option 3 -

Option 4 -

$\sqrt[]{\frac{2}{a}}$ (Elecrtrostatics)

2 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

2 months ago

Correct Option - 4

Detailed Solution:

Sol. $E = (I) (t) (A) ?{c o s}^{2} ? θ?$
$\Rightarrow (3.3) [\frac{2 π}{31.4}] [3 \times 10^{- 4}] \times \frac{1}{2}$

$\Rightarrow 0.99 \times 10^{- 4}$

0 Upvotes 0 Downvotes

Get authentic answers from experts, students and alumni that you won't find anywhere else

On Shiksha, get access to

65k Colleges
1.2k Exams
688k Reviews
1800k Answers

Community GuidelinesUser Points System

QuestionsDiscussionsTags

1 Answer

Learn more about...

Most viewed information

Most viewed information

Share Your College Life Experience

Didn't find the answer you were looking for?

Need guidance on career and education? Ask our experts

Your Question