A particle starts executing simple harmonic motion (SHM) of amplitude 'a' and total energy E. At any instant, its kinetic energy is 3E/4 then its displacement 'y' is given by:

Option 1 - y = a/2

Option 2 - y = a/√2

Option 3 - y = a√3/2

Option 4 - y = a

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Vishal Baghel | Contributor-Level 10

5 months ago

Correct Option - 4

Detailed Solution:

E = ½mω²a² . (i)
When KE = 3E/4, PE = E - KE = E/4
E/4 = ½mω²y² . (ii)
Divide eq? (i) by eq? (ii) we get
4 = a²/y² => y = a/2

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