A person in an elevator accelerating upwards with an acceleration of 2 m s–2, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand? ( g = 10 m s–2)

2 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
6 months ago

This is a Short Answer type Questions as classified in NCERT Exemplar

Explanation -initial speed of coin u= 20m/s

Acceleration of elevator =2m/s2 acceleration due to gravity = 10m/s2

Effective acceleration =g+a=12m/s2

We know that v=u +at

0= 20+ (-12)t

So t= 20/12=5/3 s

Time of ascent = time of descent

Tot

...Read more

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.8L
Reviews
|
1.8M
Answers

Learn more about...

Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025

Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering