A person in an elevator accelerating upwards with an acceleration of 2 m s–2, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand? ( g = 10 m s–2)
A person in an elevator accelerating upwards with an acceleration of 2 m s–2, tosses a coin vertically upwards with a speed of 20 m s-1. After how much time will the coin fall back into his hand? ( g = 10 m s–2)
This is a Short Answer type Questions as classified in NCERT Exemplar
Explanation -initial speed of coin u= 20m/s
Acceleration of elevator =2m/s2 acceleration due to gravity = 10m/s2
Effective acceleration =g+a=12m/s2
We know that v=u +at
0= 20+ (-12)t
So t= 20/12=5/3 s
Time of ascent = time of descent
Tot
Similar Questions for you
From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Physics NCERT Exemplar Solutions Class 11th Chapter Five 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering





