A person of mass 50 kg stands on a weighing scale on a lift. If the lift is descending with a downward acceleration of 9 m s^-2, what would be the reading of the weighing scale? (g = 10 m s^-2 )

<p>This is a Short Answer type Questions as classified in NCERT Exemplar</p><p><strong><span lang="EN-IN">Explanation –</span></strong><span lang="EN-IN"> w^'=R=m (g-a)</span></p><p><span lang="EN-IN">Mass of person =50kg</span></p><p><span lang="EN-IN">Descending acceleration= 9m/s²</span></p><p><span lang="EN-IN">Acceleration due to gravity g= 10m/s²</span></p><p><span lang="EN-IN">Apparent weight of person R= m (g-a)</span></p><p><span lang="EN-IN">= 50 (10-9)=50N</span></p><p><span lang="EN-IN">Reading in weighing scale = 50/10 =5kg</span></p>

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