A prism of refractive index μ and angle of prism A is placed in the position of minimum angle of deviation. If minimum angle of deviation is also A, then in terms of refractive index value of A is :
A prism of refractive index μ and angle of prism A is placed in the position of minimum angle of deviation. If minimum angle of deviation is also A, then in terms of refractive index value of A is :
Option 1 -
2cos⁻¹(μ/2)
Option 2 -
cos⁻¹(μ/2)
Option 3 -
sin⁻¹(μ/2)
Option 4 -
sin⁻¹((μ-1)/2)
Asked by Shiksha User
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1 Answer
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Correct Option - 1
Detailed Solution:μ = sin (A + δm)/2) / sin (A/2)
Since, δm = A
μ = sin (A) / sin (A/2) = (2sin (A/2)cos (A/2) / sin (A/2)
μ = 2cos (A/2
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