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A proton and a deuteron enter in a uniform magnetic field with equal kinetic energy in the direction perpendicular to the field. The ratio of radius of circular path is

Option 1 -

1 : 1  

Option 2 -

1 : 2

Option 3 -

2 : 1  

Option 4 -

1 : √2

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 3


    Detailed Solution:

    R = mv/qB = √2mk/qB

    Mp/Md = ½ and qp/qd =1/1

    Rp/rd = 1/√2

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