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A proton moving with velocity v along the axis approaches a circular current carrying loop as shown in figure. The magnitude of magnetic force on proton at this instant is

 

Option 1 -

μ0evR2/ 2(R2 + x2)3/2

Option 2 -

μ0eviR2/ 2(R2 + x2)3/2

Option 3 -

μ0evR2/ 4n(R2 + x2)3/2

Option 4 -

Zero

0 2 Views | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:
    Kindly go through the solution

     

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