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A proton moving with velocity v along the axis approaches a circular current carrying loop as shown in figure. The magnitude of magnetic force on proton at this instant is

 

 

Option 1 -

A

Option 2 -

B

Option 3 -

C

Option 4 -

D

0 1 View | Posted a month ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    a month ago
    Correct Option - 4


    Detailed Solution:

    Kindly go through the solutions

    Fm = q (v *B)- = q v (-i )*B (i ) = 0

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