A ray of light is incident at an angle of incidence $60°$ on the glass slab of refractive index $\sqrt[]{3}.$ After refraction, the light ray emerges out from other parallel faces and lateral shift between incident ray and emergent ray is $4\sqrt[]{3}$  cm. The thickness of the glass slab is _______cm.

$d=4\sqrt[]{3}$ cm (Lateral shift)

By Snell’s law

${\mu }_{air}sin60°={\mu }_{g}sin\theta$

θ = 30

$\Rightarrow 1\times \frac{\sqrt[]{3}}{2}=\sqrt[]{3}sin\theta$  

$sin\theta =\frac{1}{2}$  

t = 12 cm

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