A rectangular coil of wire of $500$ turns of area $10 * 5 c m^{2}$ carries a current of $2 A$ in a magnetic field of induction $2 * 10^{- 3} T$ . If the plane of the coil is parallel to the field. The torque on the coil is $(i n N m)$

Option 1 - 0.1

Option 2 - 0.01

Option 3 - 0.001

Option 4 - 1

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Alok Kumar Singh | Contributor-Level 10

4 months ago

Correct Option - 2

Detailed Solution:

Torque on a bar magnet in external uniform magnetic field is

$\overset{?}{τ} = \overset{?}{M} * \overset{?}{B}$

$\overset{?}{τ} = N I A B \sin ? 90^{0}$

$= 500 * 2 * 50 * 10^{- 4} * 2 * 10^{- 3}$

$= 0.01 N m$

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A rectangular coil of wire of 500 turns of area 10 * 5 c m 2 carries a current of 2 A in a magnetic field of induction 2 * 10 - 3 T . If the plane of the coil is parallel to the field. The torque on the coil is i n N m