A screw gauge has 50 divisions on its circular scale. The circular scale is 4 units ahead of the pitch scale marking, prior to use. Upon one complete rotation of the circular scale, a displacement of 0.5 mm is noticed on the pitch scale. The nature of zero error involved, and the least count of the screw gauge, are respectively:
A screw gauge has 50 divisions on its circular scale. The circular scale is 4 units ahead of the pitch scale marking, prior to use. Upon one complete rotation of the circular scale, a displacement of 0.5 mm is noticed on the pitch scale. The nature of zero error involved, and the least count of the screw gauge, are respectively:
Option 1 - <p>Negative, 2μm<br><!--[endif]--></p>
Option 2 - <p>Positive, 10μm<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 3 - <p>Positive, 0.1 mm<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>Positive, 0.1μm</p>
2 Views|Posted 7 months ago
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1 Answer
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Answered by
7 months ago
Correct Option - 2
Detailed Solution:
L.C. = 0.5 mm / 50 = 10? ² mm = 10? m = 10µm
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Physics Units and Measurement 2025
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