A series L – R circuit is connected to a battery of emf V. If the circuit is switched on at t = o, then the time at which the energy stored in the inductor reaches (1/n) times of its maximum value, is :
A series L – R circuit is connected to a battery of emf V. If the circuit is switched on at t = o, then the time at which the energy stored in the inductor reaches (1/n) times of its maximum value, is :
Option 1 -
L/R ln(√n/(√n+1))
Option 2 -
L/R ln((√n+1)/(√n-1))
Option 3 -
L/R ln((√n-1)/√n)
Option 4 -
L/R ln(√n/(√n-1))
Asked by Shiksha User
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1 Answer
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Correct Option - 4
Detailed Solution:i = V/r {1 - e? /? }
i? = V/rU = ½Li²
½ L (V²/r²) {1 - e? /? } = (1/n) x (LV²/2r²)
1 - e? /? = 1/√n ; e? /? = 1 - 1/√n = (√n - 1)/√n
e? /? = √n/ (√n - 1) ; rt/L = ln (√n/ (√n - 1)
T = L/r ln (√n/ (√n - 1)
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