A series LCR circuit of R = $5 Ω,$ L = 20mH and C = 0.5 $μ F$ is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is__________* 10² W.

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6 months ago

Power dissipated in cycle = P = $\frac{V_{0} l_{0}}{2} c o s ? = \frac{V_{0}^{2}}{2 z} * \frac{R}{z} = \frac{V_{0}^{2} R}{2 z}$

For resonance, z = R, so

$\Rightarrow P = \frac{V_{0}^{2}}{2 R} = \frac{250 \sqrt[]{2} * 250 \sqrt[]{2}}{2 * 5} = 12500 W a t t = 125 * 1 0^{2} W a t t$

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A series LCR circuit of R = 5 Ω , L = 20mH and C = 0.5 μ F is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is__________* 102 W.

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A series LCR circuit of R = $5 Ω,$ L = 20mH and C = 0.5 $μ F$ is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is__________* 10² W.