Alternating Current Overview Physics Alternating Current Physics Class 12th

A series LCR circuit of R = $5 Ω,$ L = 20mH and C = 0.5 $μ F$ is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is__________× 10² W.

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Vishal Baghel | Contributor-Level 10

2 months ago

Power dissipated in cycle = P = $\frac{V_{0} l_{0}}{2} c o s ? = \frac{V_{0}^{2}}{2 z} \times \frac{R}{z} = \frac{V_{0}^{2} R}{2 z}$

For resonance, z = R, so

$\Rightarrow P = \frac{V_{0}^{2}}{2 R} = \frac{250 \sqrt[]{2} \times 250 \sqrt[]{2}}{2 \times 5} = 12500 W a t t = 125 \times 1 0^{2} W a t t$

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A series LCR circuit of R = $5 Ω,$ L = 20mH and C = 0.5 $μ F$ is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is__________× 10² W.

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A series LCR circuit of R = 5 Ω , L = 20mH and C = 0.5 μ F is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is__________× 102 W.

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A series LCR circuit of R = $5 Ω,$ L = 20mH and C = 0.5 $μ F$ is connected across an AC supply of 250 V, having variable frequency. The power dissipated at resonance condition is__________× 10² W.