A small bar magnet placed with its axis at <math> <msup> <mrow> <mrow> <mn>30</mn> </mrow> </mrow> <mrow> <mrow> <mo>?</mo> </mrow> </mrow> </msup> </math> <math><msup><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msup></math> with an external field of <math> <mn>0.06</mn> <mtext> </mtext> <mi mathvariant="normal">T</mi> </math> <math><mtext></mtext></math> experiences a torque of <math></math> <math> <mn>0.018</mn> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">m</mi> </math> . The minimum work required to rotate it from its stable to unstable equilibrium position is:

τ ? = μ ? × B ? ⇒ 0.018 = μ ( 0.06 ) s i n ? 30 ? ⇒ μ = 0.6 ⇒ Work = U f - U i ⇒ 2 μ B ⇒ 7.2 × 10 - 2 J .

A small bar magnet placed with its axis at <math> <msup> <mrow> <mrow> <mn>30</mn> </mrow> </mrow> <mrow> <mrow> <mo>?</mo> </mrow> </mrow> </msup> </math> <math><msup><mrow><mrow></mrow></mrow><mrow><mrow></mrow></mrow></msup></math>&nbsp;with an external field of <math> <mn>0.06</mn> <mtext> </mtext> <mi mathvariant="normal">T</mi> </math> <math><mtext></mtext></math>&nbsp;experiences a torque of&nbsp;<math></math> <math> <mn>0.018</mn> <mi mathvariant="normal">N</mi> <mi mathvariant="normal">m</mi> </math> . The minimum work required to rotate it from its stable to unstable equilibrium position is:

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Physics NCERT Exemplar Solutions Class 11th Chapter Ten Physics Class 12th Physics Magnetism and Matter

A small bar magnet placed with its axis at $30^{?}$ $^{}$ with an external field of $0.06 T$ experiences a torque of $0.018 N m$ . The minimum work required to rotate it from its stable to unstable equilibrium position is:

Option 1 -

$11.7 * 10^{- 3} J$

Option 2 -

$9.2 * 10^{- 3} J$

Option 3 -

$7.2 * 10^{- 2} J$

Option 4 -

$6.4 * 10^{- 2} J$

3 Views | Posted 2 months ago

Asked by Shiksha User

1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

2 months ago

Correct Option - 3

Detailed Solution:

$\overset{?}{τ} = \overset{?}{μ} \times \overset{?}{B}$

$\begin{array}{l} \Rightarrow & 0.018 = μ (0.06) (s i n ? 30^{?}) \\ \Rightarrow & μ = 0.6 \\ \Rightarrow & Work = U_{f} - U_{i} \\ \Rightarrow & 2 μ B \\ \Rightarrow & 7.2 \times 10^{- 2} J . \end{array}$

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A small bar magnet placed with its axis at $30^{?}$ $^{}$ with an external field of $0.06 T$ experiences a torque of $0.018 N m$ . The minimum work required to rotate it from its stable to unstable equilibrium position is:

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A small bar magnet placed with its axis at 30 ? with an external field of 0.06 T experiences a torque of 0.018 N m . The minimum work required to rotate it from its stable to unstable equilibrium position is:

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A small bar magnet placed with its axis at $30^{?}$ $^{}$ with an external field of $0.06 T$ experiences a torque of $0.018 N m$ . The minimum work required to rotate it from its stable to unstable equilibrium position is: