A small coin is resting on the bottom of a beaker filled with liquid. A ray of light from the coin travels upto the surface of the liquid and moves along its surface. How fast is the light travelling in the liquid?

 

Option 1 -

a

Option 2 -

b

Option 3 -

c

Option 4 -

d

0 2 Views | Posted 2 weeks ago
Asked by Shiksha User

  • 1 Answer

  • R

    Answered by

    Raj Pandey | Contributor-Level 9

    2 weeks ago
    Correct Option - 4


    Detailed Solution:

    From figure, Sin  sin C=3(4)2+(3)2=35

    where C is the critical angle.

    Also,  sin C=lμa

    Sin  sin C=1aμl   [ Since l μ a = 1 a μ l ]

    Also a μ l = v e l o c i t y o f l i g h t i n a i r ( c ) v e l o c i t y o f l i g h t i n l i q u i d ( ν ) ... Sin  sin C=vc=v3×108

    or v = 3 × 1 0 8 × 3 5 = 1 . 8 × 1 0 8 m s 1

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