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A solid cylinder length is suspended symmetrically through two massless strings, as shown in the figure. The distance from the initial rest position, the cylinder should by unbinding the strings to achieve a speed of 4 ms-1, is__________cm. (take g = 10 ms-2)

0 4 Views | Posted 2 months ago
Asked by Shiksha User

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    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago

    .From conservation of energy

    mgh = 1 2 m v 2 + 1 2 l ω 2

    ⇒ m g h = 1 2 m v 2 + 1 2 m R 2 2

    10 h = 1 6 2 + 1 6 4

    h = 1.2 m = 120 cm

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