A solid metallic cube having total surface area 24 m2 is uniformly heated. if its temperature is increased by 100C, calculate the increase in volume of the cube.
(Given a = 5.0 * 10-4 0C-1).
A solid metallic cube having total surface area 24 m2 is uniformly heated. if its temperature is increased by 100C, calculate the increase in volume of the cube.
(Given a = 5.0 * 10-4 0C-1).
Option 1 - <p>2.4 × 10<sup>6</sup> cm<sup>3</sup></p>
Option 2 - <p>1.2 × 10<sup>5</sup> cm<sup>3</sup></p>
Option 3 - <p>6.0 × 10<sup>4</sup> cm<sup>3</sup></p>
Option 4 - <p>4.8 × 10<sup>5</sup> cm<sup>3</sup></p>
3 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
A
Answered by
6 months ago
Correct Option - 2
Detailed Solution:
Given
6a2 = 24
a2 = 4

a = 2m
Similar Questions for you
From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Learn more about...

Physics Thermal Properties of Matter 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering





