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Physics Gravitation Physics Class 11th Gravitation

A solid sphere of radius R gravitationally attracts a particle placed at 3R form its centre with a force F₁,. Now a spherical cavity of radius $(\frac{R}{2})$ is made in the sphere (as shown in figure) and the force becomes F₂. The value of F₁: F₂ is:

Option 1 -

36 : 25

Option 2 -

50 : 41

Option 3 -

25 : 36

Option 4 -

41 : 50

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1 Answer

Answered by

Vishal Baghel | Contributor-Level 10

a month ago

Correct Option - 2

Detailed Solution:

$F_{1} = \frac{G M m}{9 R^{2}}$

$F_{2} = \frac{G M m}{9 R^{2}} - \frac{G \frac{M}{8} m}{{(\frac{5 R}{2})}^{2}} = \frac{G M m}{R^{2}} (\frac{1}{9} - \frac{1}{50})$

$\frac{F_{1}}{F_{2}} = \frac{1}{1 - \frac{9}{50}} = \frac{50}{41}$

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A solid sphere of radius R gravitationally attracts a particle placed at 3R form its centre with a force F₁,. Now a spherical cavity of radius $(\frac{R}{2})$ is made in the sphere (as shown in figure) and the force becomes F₂. The value of F₁: F₂ is:

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A solid sphere of radius R gravitationally attracts a particle placed at 3R form its centre with a force F1,. Now a spherical cavity of radius ( R 2 ) is made in the sphere (as shown in figure) and the force becomes F2. The value of F1: F2 is:

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A solid sphere of radius R gravitationally attracts a particle placed at 3R form its centre with a force F₁,. Now a spherical cavity of radius $(\frac{R}{2})$ is made in the sphere (as shown in figure) and the force becomes F₂. The value of F₁: F₂ is: