A sphere of radius 'a' and mass 'm' rolls along a horizontal plane with constant speed v0. It encounters and inclined plane at angle θ and climbs upward. Assuming that it rolls without slipping, how far up the sphere will travel?

Option 1 - <p><math><mrow><mfrac><mrow><mn>2</mn></mrow><mrow><mn>5</mn></mrow></mfrac><mfrac><mrow><msubsup><mrow><mi>v</mi></mrow><mrow><mn>0</mn></mrow><mrow><mn>2</mn></mrow></msubsup></mrow><mrow><mi>g</mi><mtext> </mtext><mi>s</mi><mi>i</mi><mi>n</mi><mtext> </mtext><mi>θ</mi></mrow></mfrac></mrow></math>&nbsp;</p>
Option 2 - <p><math><mrow><mfrac><mrow><msubsup><mrow><mi>v</mi></mrow><mrow><mn>0</mn></mrow><mrow><mn>2</mn></mrow></msubsup></mrow><mrow><mn>5</mn><mi>g</mi><mtext> </mtext><mi>s</mi><mi>i</mi><mi>n</mi><mi>θ</mi></mrow></mfrac></mrow></math></p>
Option 3 - <p><math><mrow><mfrac><mrow><msubsup><mrow><mi>v</mi></mrow><mrow><mn>0</mn></mrow><mrow><mn>2</mn></mrow></msubsup></mrow><mrow><mn>2</mn><mi>g</mi><mtext> </mtext><mi>s</mi><mi>i</mi><mi>n</mi><mi>θ</mi></mrow></mfrac></mrow></math></p>
Option 4 - <p><math><mrow><mfrac><mrow><mn>1</mn><mn>0</mn><msubsup><mrow><mi>v</mi></mrow><mrow><mn>0</mn></mrow><mrow><mn>2</mn></mrow></msubsup></mrow><mrow><mn>7</mn><mi>g</mi><mi>s</mi><mi>i</mi><mi>n</mi><mi>θ</mi></mrow></mfrac></mrow></math></p>
6 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
P
7 months ago
Correct Option - 4
Detailed Solution:

Using conservation of energy between initial and final position shown :

[12 (25ma2) (V0a)2+12mV02]+0=mglsinθ

710mV02=mglsinθ

l=7v0210gsinθ

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Physics Work, Energy and Power 2021

Physics Work, Energy and Power 2021

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