A stone is dropped from the top of a building. When it crosses a point 5m below the top, another stone starts to fall from a point 25m below the top. Both stones reach the bottom of building simultaneously. The height of the building is

Option 1 - <p>35m</p>
Option 2 - <p>45m</p>
Option 3 - <p>50m</p>
Option 4 - <p>25m</p>
12 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
P
6 months ago
Correct Option - 2
Detailed Solution:

When second stone is released

Equation for first ball:

x+20=10t+12gt2

Equation for second ball :

x=12gt2

Using these two equation

20 = 10t t = 2 sec

x=12*10*4=20m

H = 20 + 20 + 5 = 45 m.

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

Physics Motion in Straight Line 2025

Physics Motion in Straight Line 2025

View Exam Details

Most viewed information

Summary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering