A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A . The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as $4 π * 1 0^{- 7} SI$ units):

Option 1 - 44 mT

Option 2 - 4.4 T

Option 3 - 4.4 mT

Option 4 - 44 T

4 Views|Posted 6 months ago

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Answered by

Alok Kumar Singh | Contributor-Level 10

6 months ago

Correct Option - 3

Detailed Solution:

The magnitude of magnetic field due to circular coil of $N$ turns is given by

$B_{C} = \frac{μ_{0} i N}{2 R}$

$= \frac{4 π * 1 0^{- 7} * 7 * 100}{2 * 0.1}$

$= 4.4 * 1 0^{- 3} T$

$= 4.4 mT$

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