A tightly wound 100 turns coil of radius 10 cm carries a current of 7 A . The magnitude of the magnetic field at the centre of the coil is (Take permeability of free space as 4π×107SI  units):

Option 1 -

44 mT

Option 2 -

4.4 T

Option 3 -

4.4 mT

Option 4 -

44 T

0 4 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • A

    Answered by

    alok kumar singh | Contributor-Level 10

    2 months ago
    Correct Option - 3


    Detailed Solution:

    The magnitude of magnetic field due to circular coil of N  turns is given by

    B C = μ 0 i N 2 R

    = 4 π × 1 0 7 × 7 × 1 0 0 2 × 0 . 1

    =4.4×103 T

    =4.4mT

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