A train, standing in a station yard, blows a whistle of frequency 400 Hz in still air. The wind starts blowing in the direction from the yard to the station with a speed of 10m/s. Given that the speed of sound in still air is 340m/s,

(a) The frequency of sound as heard by an observer standing on the platform is 400Hz.

(b) The speed of sound for the observer standing on the platform is 350m/s.

(c) The frequency of sound as heard by the observer standing on the platform will increase.

(d) The frequency of sound as heard by the observer standing on the platform will decrease.

0 4 Views | Posted 3 months ago
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    Answered by

    Payal Gupta | Contributor-Level 10

    3 months ago

    This is a multiple choice answer as classified in NCERT Exemplar

    (a, b) vo=400Hz, v=340m/s

    Vm=10m/s

    (a) as both source and observer are stationary, hence frequency observed will be same as natural frequency vo=400Hz

    (b) the speed of sound v=v+vw= 340+10=350m/s

    (c) there will be on effect on frequency because there is no relative motion between source and observer hence c, d are incorrect.

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