A transformer operating at primary voltage 8 kV and secondary voltage 160V serves a load of 80 k.W. Assuming the transformer to be ideal with purly resistive load and working on unity power factor, the loads in the primary and secondary circuit would be

Option 1 -

 800 Ω 1.06 Ω

Option 2 -

10 Ω and 500 Ω

Option 3 -

800 Ω and 0.32 Ω

Option 4 -

1.06 Ω and 500 Ω

0 6 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 3


    Detailed Solution:

     VP=8kV, VS=160vP=80kW

    (Purely resistive load)

    P=VI=VP2RP=VS2RS

    RS=VS2P=160×16080×103=320×103=0.32Ω

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