A uniform heavy rod of weight 10kg ms-2, cross-sectional area 100 cm2f and length 20 cm is hanging from a fixed support. Young modulus of the material of the rod is 2 * 1011 Nm-2. Neglecting the lateral concentration, find the elongation of rod due to its own weight:

Option 1 - <p>2 × 10<sup>-9</sup> m</p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mrow> <mn>5</mn> <mo>×</mo> <mn>1</mn> <msup> <mrow> <mn>0</mn> </mrow> <mrow> <mn>1</mn> <mn>0</mn> </mrow> </msup> <mi>m</mi> </mrow> </math> </span></p>
Option 3 - <p>4 × 10<sup>-8</sup> m</p>
Option 4 - <p>5 × 10<sup>-</sup><sup>8</sup> m</p>
13 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
R
7 months ago
Correct Option - 2
Detailed Solution:

W = 10 kg m/s2

A = 100 cm2

l = 2 0 c m

Y = 2 * 1011 N/m2

Y = F l A Δ l Δ l = F l A Y

For elemental mass of length, dx

Change in its length

Δ l = 5 * 1 0 1 0 m

 

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Physics Mechanical Properties of Solids 2025

Physics Mechanical Properties of Solids 2025

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