A uniform rod of length 'l' is pivoted at one of its ends on a vertical shaft of negligible radius. When the shaft rotates at angular speed the rod makes an angle with it (see figure). To find equate the rate of change of angular momentum (direction going into the paper) about the centre of mass (CM) to the torque provided by the horizontal and vertical forces and about the . The value of is then such that:
A uniform rod of length 'l' is pivoted at one of its ends on a vertical shaft of negligible radius. When the shaft rotates at angular speed the rod makes an angle with it (see figure). To find equate the rate of change of angular momentum (direction going into the paper) about the centre of mass (CM) to the torque provided by the horizontal and vertical forces and about the . The value of is then such that:
Torque of centrifugal force about
(about A)

Similar Questions for you
From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
Learn more about...

Physics System of Particles and Rotational Motion 2025
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
See what others like you are asking & answering






