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A vertical electric field of magnitude 4.9 × 105 N/C just prevents a water droplet of a mass 0.1 g from falling. The value of charge on the droplet will 

(Given g = 9.8 m/s2)

Option 1 -

1.6 * 10-9 C

Option 2 -

2.0 * 10-9 C       

Option 3 -

3.2 * 10-9 C

Option 4 -

0.5 * 10-9 C

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 2


    Detailed Solution:

    qE = mg

    ⇒ q = m g E = 0 . 1 1 0 0 0 × 9 . 8 4 . 9 × 1 0 5         

    q = 2 × 10-9 C

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