A vertical electric field of magnitude 4.9 * 105 N/C just prevents a water droplet of a mass 0.1 g from falling. The value of charge on the droplet will 

(Given g = 9.8 m/s2)

Option 1 - <p>1.6 × 10<sup>-9</sup> C</p>
Option 2 - <p>2.0 × 10<sup>-9</sup> C&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</p>
Option 3 - <p>3.2 × 10<sup>-9</sup> C</p>
Option 4 - <p>0.5 × 10<sup>-9</sup> C</p>
2 Views|Posted 6 months ago
Asked by Shiksha User
1 Answer
V
6 months ago
Correct Option - 2
Detailed Solution:

qE = mg

q = m g E = 0 . 1 1 0 0 0 * 9 . 8 4 . 9 * 1 0 5         

q = 2 * 10-9 C

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Physics Ncert Solutions Class 12th 2023

Physics Ncert Solutions Class 12th 2023

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