A very long conducting wire is bent in a semi-circular shape from $A$ to $B$ as shown in figure. The magnetic field at point $P$ for steady current configuration is given by:

Option 1 -

. $\frac{μ_{0} i}{4 R} [1 - \frac{2}{π}]$ pointed into the page

Option 2 -

$\frac{μ_{0} i}{4 R}$ pointed into the page

Option 3 -

$\frac{μ_{0} i}{4 R}$ pointed away from the page

Option 4 -

$\frac{μ_{0} i}{4 R} [1 - \frac{2}{π}]$ pointed away from page

3 Views | Posted a month ago

Asked by Shiksha User

1 Answer

Answered by

alok kumar singh | Contributor-Level 10

a month ago

Correct Option - 2

Detailed Solution:

$V_{P} = V_{q} + V_{- q}$

$\begin{array}{r} = (\frac{K q}{5 - 3} + \frac{K (- q)}{5 + 3}) * 10^{2} \\ = (\frac{K q}{2} - \frac{K q}{8}) * 10^{2} \\ = (\frac{3 K q}{8}) * 10^{2} \end{array}$

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A very long conducting wire is bent in a semi-circular shape from $A$ to $B$ as shown in figure. The magnetic field at point $P$ for steady current configuration is given by:

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A very long conducting wire is bent in a semi-circular shape from A to B as shown in figure. The magnetic field at point P for steady current configuration is given by:

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A very long conducting wire is bent in a semi-circular shape from $A$ to $B$ as shown in figure. The magnetic field at point $P$ for steady current configuration is given by: