A vessel contains 16g of hydrogen and 128g of oxygen at standard temperature and pressure. The volume of the vessel in cm³ is

<p>According to question, we can write</p><p>Total moles of gas = n = n_Oxygen+ n_Oxygen =&nbsp;<math><mrow><mfrac><mrow><mn>1</mn><mn>6</mn></mrow><mrow><mn>2</mn></mrow></mfrac><mo>+</mo><mfrac><mrow><mn>1</mn><mn>2</mn><mn>8</mn></mrow><mrow><mn>3</mn><mn>2</mn></mrow></mfrac><mo>=</mo><mn>1</mn><mn>2</mn><mi>m</mi><mi>o</mi><mi>l</mi><mi>e</mi><mi>s</mi></mrow></math></p><p>Volume of gas = 12 × 22.4 litre = 268.8 litre = 2.688 × 10⁵cm3&nbsp;<math><mrow><mo>≈</mo><mn>2</mn><mn>7</mn><mo>×</mo><mn>1</mn><msup><mrow><mn>0</mn></mrow><mrow><mn>4</mn></mrow></msup><mi>c</mi><msup><mrow><mi>m</mi></mrow><mrow><mn>3</mn></mrow></msup></mrow></math></p>

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