A wheel is rotating freely with an angular speed ω on a shaft. The moment of inertia of the wheel is I and the moment of inertia of the shaft is negligible. Another wheel of moment of inertia 3I initially at rest is suddenly coupled to the same shaft. The resultant fractional loss in the kinetic energy of the system is:
A wheel is rotating freely with an angular speed ω on a shaft. The moment of inertia of the wheel is I and the moment of inertia of the shaft is negligible. Another wheel of moment of inertia 3I initially at rest is suddenly coupled to the same shaft. The resultant fractional loss in the kinetic energy of the system is:
Option 1 -
3/4
Option 2 -
5/6
Option 3 -
1/4
Option 4 -
0
Asked by Shiksha User
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1 Answer
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Correct Option - 1
Detailed Solution:As Torque net = 0
Hence, L = constant
Iω = (3I + I)ω'
ω' = ω/4
Loss in K.E. = 1/2 Iω² - 1/2 (I + 3I)ω²/16 = 1/2 Iω² (1 - 1/4)
Fractional loss = (3/4 * 1/2 Iω²)/ (1/2 Iω²) = 3/4
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