A wire X of length 50cm carrying a current of 2A is placed parallel to a long wire Y of length 5m. The wire Y current of 3A. The distance between two wires is 5cm and currents flow in the same direction. The force acting on the wire Y is

 

Option 1 -

1.2 * 10-5 N directed towards wire X.                          

...more

Option 2 -

1.2 * 10-4 N directed away from wire X.

Option 3 -

1. * 10-4 N directed towards wire X.    

Option 4 -

1.2 * 10-5 N directed towards wire X.

0 6 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    2 months ago
    Correct Option - 1


    Detailed Solution:

    Fx-y = μ0i1i22πr× (.5)

    =2×107×6×0.50.05

    =65×105N=1.2×105

    Force on Y = 1.2 × 105N towards ‘x’

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