According to Bohr atom model, in which of the following transitions will the frequency be maximum?

Option 1 - n = 3 to n = 2

Option 2 - n = 4 to n = 3

Option 3 - n = 2 to n = 1

Option 4 - n = 5 to n = 4

2 Views|Posted 6 months ago

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Answered by

Vishal Baghel | Contributor-Level 10

6 months ago

Correct Option - 3

Detailed Solution:

$Δ E = h v \to (\frac{1}{n_{2}^{2}} - \frac{1}{n_{1}^{2}})$

(1) n₁ = 3, n₂ = 2

$(\frac{1}{2^{2}} - \frac{1}{3^{2}}) = \frac{9 - 4}{36} = \frac{5}{36}$

(2) n₁ = 4, n₂ = 3

$(\frac{1}{3^{2}} - \frac{1}{4^{2}}) = \frac{16 - 9}{144} = \frac{7}{144}$

(3) n₁ = 2, n₂ = 1

$(\frac{1}{1^{2}} - \frac{1}{2^{2}}) = \frac{4 - 1}{4} = \frac{3}{4}$

(4) n₁ = 5, n₂ = 4

$(\frac{1}{4^{2}} - \frac{1}{5^{2}}) = \frac{25 - 16}{400} = \frac{9}{400}$

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