Amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass = 500g, Decay constant = 20g/s then how much time is required for the amplitude of the system to drop to half of its initial value? (ln 2 = 0.693)
Amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass = 500g, Decay constant = 20g/s then how much time is required for the amplitude of the system to drop to half of its initial value? (ln 2 = 0.693)
Option 1 -
34.65 s
Option 2 -
15.01 s
Option 3 -
17.32 s
Option 4 -
0.034 s
Asked by Shiksha User
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1 Answer
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Correct Option - 1
Detailed Solution:As we know that for damping Oscillation
A = A? e? / (²? ) ⇒ t? /? = ln (2)2m/b = (0.693 × 2 × 500)/20 = 34.65 s
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