An aeroplane, with its wings spread 10m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth’s field at that part is 2.5 × 10-4Wb/m2 and the angle of dip is 60°. The emf induced between the tips of the plane wings will be

Option 1 -

88.37mV 

Option 2 -

54.125mV  

Option 3 -

62.50mV       

Option 4 -

108.25mV

0 3 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • P

    Answered by

    Payal Gupta | Contributor-Level 10

    2 months ago
    Correct Option - 4


    Detailed Solution:

    Bv = B sin 60°

    Bv=2.5×104×32

    Emf=Bv×v×l=2.5×104×32×180×518×1=108.25×103volts

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