An aeroplane, with its wings spread 10m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth’s field at that part is 2.5 × 10-4Wb/m2 and the angle of dip is 60°. The emf induced between the tips of the plane wings will be…………..
An aeroplane, with its wings spread 10m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth’s field at that part is 2.5 × 10-4Wb/m2 and the angle of dip is 60°. The emf induced between the tips of the plane wings will be…………..
Option 1 -
88.37mV
Option 2 -
54.125mV
Option 3 -
62.50mV
Option 4 -
108.25mV
-
1 Answer
-
Correct Option - 4
Detailed Solution:Bv = B sin 60°
->
Similar Questions for you
Kindly go through the solution
M = φ? /I? = (B? A? )/I? = [ (μ? I? /2R? )πR? ²]/I?
[Diagram of two concentric coils]
M = (μ? πR? ²)/ (2R? )
M ∝ R? ²/R?
(A) The magnet's entry
R =
L = 2 mH
E = 9V
Just after the switch ‘S’ is closed, the inductor acts as open circuit.
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else
Sign Up on ShikshaOn Shiksha, get access to
- 65k Colleges
- 1.2k Exams
- 686k Reviews
- 1800k Answers



