An aeroplane, with its wings spread 10m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth's field at that part is 2.5 * 10-4Wb/m2 and the angle of dip is 60°. The emf induced between the tips of the plane wings will be…………..
An aeroplane, with its wings spread 10m, is flying at a speed of 180 km/h in a horizontal direction. The total intensity of earth's field at that part is 2.5 * 10-4Wb/m2 and the angle of dip is 60°. The emf induced between the tips of the plane wings will be…………..
Bv = B sin 60°
->
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Kindly go through the solution
M = φ? /I? = (B? A? )/I? = [ (μ? I? /2R? )πR? ²]/I?
[Diagram of two concentric coils]
M = (μ? πR? ²)/ (2R? )
M ∝ R? ²/R?
(A) The magnet's entry
R =
L = 2 mH
E = 9V
Just after the switch ‘S’ is closed, the inductor acts as open circuit.
PR = l2R
=> 640 = (8)2 R
R =
from (i) 64 =
L = 2H
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Physics Ncert Solutions Class 12th 2023
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