An automobile of mass 'm' accelerates starting from origin and initially at rest, while the engine supplies constant power P. The position is given as a function of time by:
An automobile of mass 'm' accelerates starting from origin and initially at rest, while the engine supplies constant power P. The position is given as a function of time by:
Option 1 - <p>(8P/9m)¹/² t³/²</p>
Option 2 - <p>(8P/9)¹/² t³/²</p>
Option 3 - <p>(9m/8P)¹/² t³/²<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
Option 4 - <p>(9m/8P)¹/² t³/²<br><!-- [if !supportLineBreakNewLine]--><br><!--[endif]--></p>
3 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
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Answered by
7 months ago
Correct Option - 4
Detailed Solution:
P = Fv = (ma)v = m (dv/dt)v
P dt = mv dv
∫P dt = ∫mv dv
Pt = ½mv²
v = √ (2Pt/m)
dx/dt = √ (2P/m) t¹/²
x = √ (2P/m) ∫t¹/² dt = √ (2P/m) * (2/3)t³/²
Squaring to match options:
x² = (8P/9m) t³
This does not match. Let's re-examine the options.
Position x is proportional to t³/².
x = (8P/9m)¹/² t³/²
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Physics Work, Energy and Power 2021
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