An electric appliance supplies 6000 J/min heat to the system. If the system delivers a power of 90W. How long it would take to increase the internal energy by 2.5 × 103 J?
An electric appliance supplies 6000 J/min heat to the system. If the system delivers a power of 90W. How long it would take to increase the internal energy by 2.5 × 103 J?
Option 1 -
4.1 * 101s
Option 2 -
2.4 * 103s
Option 3 -
2.5 * 101s
Option 4 -
2.5 * 102s
-
1 Answer
-
Correct Option - 4
Detailed Solution:= 10 J
second
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Heat is path dependent so path function but internal energy does not depend on path chosen.
Work Area
->W =
= 1200J
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