An electric bulb of 500 watt at 100 volt is used in a circuit having a 200V supply. Calculate resistance R to be connected in series with the bulb so that the power delivered by the bulb is 500W.

Correct Option - 1


Detailed Solution:

As power delivered by the bulb is 500 W, potential difference across it should be 00 V. Thus,

  $R=R_{bulb}=\frac{100^2}{500}=20\Omega$

 

            

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