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An electron having de-Broglie wavelength λ  is indent on a target in a X-ray tube. Cut-off wavelength of emitted X-ray is:

Option 1 -

0

Option 2 -

2 m c     λ 2 h

Option 3 -

h c m c

Option 4 -

2 m 2 c 2 λ 2 h 2

0 2 Views | Posted 2 months ago
Asked by Shiksha User

  • 1 Answer

  • V

    Answered by

    Vishal Baghel | Contributor-Level 10

    2 months ago
    Correct Option - 2


    Detailed Solution:

    According to de-Broglie’s hypothesis

    λ = h m v ⇒ p = m v = h λ ⇒ K = p 2 2 m = h 2 2 m λ 2

    Cut-off wavelength of emitted X-ray = h c K = h c × 2 m λ 2 h 2 = 2 m c λ 2 h

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