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An electron moves in the field produced by a charged sphere of radius 10cm along the radius connecting the points separated by 12 and 15 cm from the centre of the sphere. The velocity of the electron changes thereby from 2 × 105 to 2 × 106 m/s. Determine the surface charge (in nC/m2) density of the sphere. (Mass of electron = 9.1 × 10-31kg)

0 4 Views | Posted 3 weeks ago
Asked by Shiksha User

  • 1 Answer

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    Answered by

    Vishal Baghel | Contributor-Level 10

    3 weeks ago

    k Q e 0 . 1 2 + 1 2 m u 2 = k Q e 0 . 1 5 + 1 2 m u 2

    k Q e × 0 . 0 3 0 . 1 2 × 0 . 1 5 = 1 2 m × ( v 2 − u 2 )

    Q = 9 . 1 × 9 9 × 1 0 − 1 1 1 2

    = 7 5 . 0 7 5 × 1 0 − 1 2 4 π × ( 0 . 1 ) 2 = 5 . 9 7     n C / m 2

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