An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 k g . The mass of the elevator itself is 920 k g and it moves with a constant speed of 3 m / s . the frictional force opposing the motion is 6000 N . If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator g = 10 m / s 2  must be at least:

Option 1 - <p><span class="mathml" contenteditable="false"> <math> <mn>56300</mn> <mtext> </mtext> <mi mathvariant="normal">W</mi> </math> </span></p>
Option 2 - <p><span class="mathml" contenteditable="false"> <math> <mn>66000</mn> <mtext> </mtext> <mi mathvariant="normal">W</mi> </math> </span></p>
Option 3 - <p><span class="mathml" contenteditable="false"> <math> <mn>62360</mn> <mtext> </mtext> <mi mathvariant="normal">W</mi> </math> </span></p>
Option 4 - <p><span class="mathml" contenteditable="false"> <math> <mn>48000</mn> <mtext> </mtext> <mi mathvariant="normal">W</mi> </math> </span></p>
3 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
A
8 months ago
Correct Option - 2
Detailed Solution:

Net force on motor will be

F min   = [ 920 + 68 ( 10 ) ] g + 6000

= 22000 N

So, required power for motor

P min   = F ? min   v ? = 22000 * 3 = 66000   watt  

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Physics Work, Energy and Power 2021

Physics Work, Energy and Power 2021

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