Physics Alternating Current Alternating Current Overview Class 12th Physics

An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance ' R' are connected in series to an ac source of potential difference ' V volts as shown in figure. Potential difference across L, C and R is 40 V, 10 V and 40 V, respectively. The amplitude of current flowing through LCR series circuit is 10√2 A. The impedance of the circuit is:

Option 1 - <p>4√2 Ω<br><br></p>

Option 2 - <p>5/√2 Ω<br><br></p>

Option 3 - <p>4 Ω</p>

Option 4 - <p>5 Ω</p>

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Answered by

Vishal Baghel | Contributor-Level 10

5 months ago

Correct Option - 2

Detailed Solution:

Diameter = main scale reading + (circular scale reading * least count)
Diameter = 0 + (52 * 0.01 mm) = 0.52 mm = 0.052 cm.
In the RLC circuit:
Given I? = 10√2 A, so I? = I? /√2 = 10 A.
V? = √ [V? ² + (V? - V? )²] = √ [40² + (40 - 10)²] = √ [1600 + 30²] = √ [1600 + 900] = √2500 = 50 V.
Impedance Z = V? /

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