An iron rod of volume and relative permeability 1000 is placed as core in a solenoid with 10 turns/cm. If a current of is passed through the solenoid, then the magnetic moment of the rod will be:
M = µ? NiA Here µ? = Relative permeability N = Number of turns i = Current A = Area of cross section M = µ? NiA = µ? nliA M = µ? niV = 1000 (1000) (0.5) (10? ³) = 500 = 5 × 10²Am²
<p>M = µ? NiA<br>Here<br>µ? = Relative permeability<br>N = Number of turns<br>i = Current<br>A = Area of cross section<br>M = µ? NiA = µ? nliA<br>M = µ? niV = 1000 (1000) (0.5) (10? ³) = 500 = 5 × 10²Am²</p>
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