Semiconductors Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen Class 12th Physics

An n.p.n transistor with current gain = 100in common emitter configuration is shown in figure. The output voltage of the amplifier will be

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Vishal Baghel | Contributor-Level 10

6 months ago

n.p.m. transistor current gain B = 100

As, B = $\frac{I_{C}}{I_{B}} V o l t a g e g a i n, \frac{V_{o u t}}{V_{i n}} = (\frac{I_{C}}{I_{B}}) \frac{R_{2}}{R_{i}}$

$V_{o u t} = \frac{B R_{2}}{R_{i n}} V i n$

$\frac{1 0^{3}}{1 0^{3}} V = 1 v$

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Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen 2025

Physics NCERT Exemplar Solutions Class 12th Chapter Fourteen 2025

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