An object is taken to a height above the surface of earth at a distance 5 4 R  from the centre of the earth. Where radius of earth, R = 6400km. The percentage decrease in the weight of the object will be

Option 1 - <p>36%&nbsp; &nbsp;</p>
Option 2 - <p>50%&nbsp;</p>
Option 3 - <p>64%</p>
Option 4 - <p>25%</p>
6 Views|Posted 8 months ago
Asked by Shiksha User
1 Answer
P
8 months ago
Correct Option - 1
Detailed Solution:

As we know that gP=g (RR+h)2=g (R54R)2=16g25

Δg=ggP=9g25

The percentage decrease in the weight of the object = Δgg*100=36%

Thumbs Up IconUpvote Thumbs Down Icon

Taking an Exam? Selecting a College?

Get authentic answers from experts, students and alumni that you won't find anywhere else.

On Shiksha, get access to

66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers

Learn more about...

physics ncert exemplar solutions class 12th chapter two 2025

physics ncert exemplar solutions class 12th chapter two 2025

View Exam Details

Most viewed information

SummarySummary

Share Your College Life Experience

Didn't find the answer you were looking for?

Search from Shiksha's 1 lakh+ Topics

or

Ask Current Students, Alumni & our Experts

Have a question related to your career & education?

or

See what others like you are asking & answering