An object of mass 'm' is being moved with a constant velocity under the actin of an applied force of 2N along a frictionless surface with following surface profile.
The correct applied force vs distance graph will be:
An object of mass 'm' is being moved with a constant velocity under the actin of an applied force of 2N along a frictionless surface with following surface profile.
The correct applied force vs distance graph will be:
Option 1 - <p>(a)</p>
Option 2 - <p>(b)</p>
Option 3 - <p>(c)</p>
Option 4 - <p>(d)</p>
3 Views|Posted 7 months ago
Asked by Shiksha User
1 Answer
A
Answered by
7 months ago
Correct Option - 1
Detailed Solution:
Object is moving in upward direction with constant velocity so in upward motion (+2N) and for downward motion (-2N) So option (1) is correct representation.
Similar Questions for you
From A to B the process is isobaric

= W = 2 × R (600 - 350)
= 500 R
Taking an Exam? Selecting a College?
Get authentic answers from experts, students and alumni that you won't find anywhere else.
On Shiksha, get access to
66K
Colleges
|
1.2K
Exams
|
6.9L
Reviews
|
1.8M
Answers
Learn more about...

Physics Work, Energy and Power 2021
View Exam DetailsMost viewed information
SummaryDidn't find the answer you were looking for?
Search from Shiksha's 1 lakh+ Topics
or
Ask Current Students, Alumni & our Experts
Have a question related to your career & education?
or
See what others like you are asking & answering







