An observer moves towards a stationary source of sound with a velocity one-fourth of the velocity of sound. What is the percentage increase in the apparent frequency?
An observer moves towards a stationary source of sound with a velocity one-fourth of the velocity of sound. What is the percentage increase in the apparent frequency?
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f? = 420 Hz
f? = (V? + V)/ (V? - V) f? = 490
(330 + V)/ (300 - V) 420 = 490
(330 + V)6 = 7 (330 – V)
13 V = 330
V = 33/13 (m/s)
= 91 (km/hr)
f? = frequency heard by wall = f_s (v_s/ (v_s - v_c)
f? = frequency heard by driver after reflection from wall
f? = (v_s + v_c)/v_s)f? = (v_s + v_c)/ (v_s - v_c)f?
f? /f? = (v_s - v_c)/ (v_s + v_c)
48/44 = (v_s - v_c)/ (v_s + v_c)
12 (v_s + v_c) = 11 (v_s - v_c)
23v_c = v_s
v_c = v_s/23 = 345/23 = 15 m/s
=
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