As shown in the figure an inductor of inductance 200 mH is connected to an AC source of emf 220 V and frequency 50 Hz. The instantaneous voltage of the source is 0 V when the peak value of current is a π A .  The value of a is __________.

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6 months ago

Let l = l0 cos wt

Then v = v0 sinwt

at t = 0, v = 0

but l = l0

l r m s = l 0 2

V r m s = l r m s z      

2 2 0 = l 0 2 ( X L )        

2 2 0 = l 0 2 ( 2 π * 5 0 * 2 0 0 * 1 0 3 )        

2 2 0 = l 0 2 ( 2 0 π )

l 0 = 2 2 0 2 2 0 π  

l 0 = 1 1 2 π = a π

a = 121 * 2

a = 242

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Physics Alternating Current 2025

Physics Alternating Current 2025

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